This feature is not available right now. Please try again later. The RPG you've always been waiting for has finally arrived on Android devices! Anima is an action RPG (hack'n slash) videogame inspired by the greatest old school games and made with passion by RPG lovers for RPG lovers, and released in 2019.
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You can.You are given that that first (the faster) pump works as effectively as three slower pumps.Therefore, you may think that 4 = 3+1 slower pumps, actually, work, and these 4 pumps fill the tank in 12 minutes.Hence, one single slower pump can fill the tank in 4.12 = 48 minutes, working alone.Next, since the faster pump is 3 times as fast, it needs only 48/3 = 16 minutes to fill the tank, working alone.Solved.-It is a standard and typical joint work problem.There is a wide variety of similar solved joint-work problems with detailed explanations in this site. See the lessons-Read them and get be trained in solving joint-work problems.Also, you have this free of charge online textbook in ALGEBRA-I in this site-.The referred lessons are the part of this textbook under the topic' Rate of work and joint work problems' of the section ' Word problems'.Save the link to this online textbook together with its descriptionFree of charge online textbook in ALGEBRA-Iyour archive and use it when it is needed.Answer by. You canSince the faster pump works 3 times as fast as the slower, in filling the tank the faster pump does 3/4 of the work and the slower pump does 1/4.The faster pump fills 3/4 of the tank in 12 minutes; the time it would take that pump alone to fill the tank is 12.(4/3) = 16 minutes.The slower pump fills 1/4 of the tank in 12 minutes; the time it would take that pump alone to fill the tank is 12.4 = 48 minutes.ANSWERS:Faster pump alone: 16 minutesSlower pump alone: 48 minutesAnswer by. You canThis problem may seem puzzling at first since the actual rate of filling, and the actual capacity of the tank are not given. However it can be solved as follows.Let vol of tank be X litresLet rate of P1 be y litres/minThen rate of P2 is litres/minIf they work together, rate is litres /minand it takes 12 min.So capacity of tank = litresSo if P1 alone is used, time taken=If P2 alone is used, time taken=Solved.: HiA plane took off 1 hour later for its destination 3000km away. In order to reach the destination on time the pilot increased speed by 500km per hour.What is the new speed of the plane.ThanksAnswer by. You can.Let x be the new speed, in km/h.Then the regular speed is (x-500) km/h.The regular flight time is hours.The new time flight is hours.The difference is one hour (1 hour), which gives you THIS 'time equation'- = 1 hour.To solve the equation, multiply both sides by x.(x-500).
Notepad 64-bit is a free source code editor and the app replacement that supports several languages. Running in the MS Windows environment, its use is governed by GPL Licence. The for your Windows PC!Based on a powerful editing component Scintilla, Notepad plus plus is written in C and uses pure Win32 API and STL which ensures a higher execution speed and smaller program size.
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